Le 01/10/2015 22:20, Samuel Gougeon a écrit :
.../...
a) if stop is %nan => error
b) if start or step is %nan => returns %nan
.
could be split into
b1) if start is %nan => return %nan
b2) if step is %nan => return start: the first element is well
defined and could be returned.
c) = iii): if start < end && step < 0 => return [], even if start,
step or stop is/are inf/-inf
d) = iv): if start > end && step > 0 => return [], even if start, step
or stop is/are inf/-inf
e) if|stop| ~= inf && |step|==inf => return start (even if it is +-inf)
f) if start or stop or both are inf or -inf => error, even when |step|
is inf
g) otherwise: normal computation.
Samuel
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