Hello,
I am wondering about the following answers:
--> s = %nan;
--> or(s)
ans =
F
--> and(s)
ans =
T
With this last answer, we have a case such that although all entries are
false -- otherwiseor() would answer %T--, and()applied to them is True.
Is there a reason for that, or is it a bug?
This behavior was already present in Scilab 4.1.2 and is still here in
Scilab 6.0-b1
Samuel
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