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https://issues.apache.org/jira/browse/MAHOUT-823?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=13118721#comment-13118721
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Sean Owen commented on MAHOUT-823:
----------------------------------

I did the homework, and came up with the following result. The substance of the 
patch is now this (as well as removing other dot() implementations):

{code}
    // Crude rule of thumb: when a sequential-access vector, with O(log n) 
lookups, has about
    // 2^n elements, its lookups take longer than a dense / random access 
vector (with O(1) lookups) by
    // about a factor of (0.71n - 12.3). This holds pretty well from n=19 up to 
at least n=23 according to my tests;
    // below that lookups are so fast that this difference is near zero.

    int thisNumNonDefault = getNumNondefaultElements();
    int thatNumNonDefault = x.getNumNondefaultElements();
    // Default: dot from smaller vector to larger vector
    boolean reverseDot = thatNumNonDefault < thisNumNonDefault;

    // But, see if we should override that -- is exactly one of them sequential 
access and so slower to lookup in?
    if (isSequentialAccess() != x.isSequentialAccess()) {
      double log2ThisSize = Math.log(thisNumNonDefault) / LOG2;
      double log2ThatSize = Math.log(thatNumNonDefault) / LOG2;
      // Only override when the O(log n) factor seems big enough to care about:
      if (log2ThisSize >= 19.0 && log2ThatSize >= 19.0) {
        double dotCost = thisNumNonDefault;
        if (x.isSequentialAccess()) {
          dotCost *= 0.71 * log2ThatSize - 12.3;
        }
        double reverseDotCost = thatNumNonDefault;
        if (isSequentialAccess()) {
          reverseDotCost *= 0.71 * log2ThisSize - 12.3;
        }
        reverseDot = reverseDotCost < dotCost;
      }
    }

    if (reverseDot) {
      return x.dot(this);
    }
{code}

Thoughts?
                
> RandomAccessSparseVector.dot with another non-sequential vector can be 
> extremely non-symmetric in its performance
> -----------------------------------------------------------------------------------------------------------------
>
>                 Key: MAHOUT-823
>                 URL: https://issues.apache.org/jira/browse/MAHOUT-823
>             Project: Mahout
>          Issue Type: Improvement
>          Components: Math
>    Affects Versions: 0.5
>            Reporter: Eugene Kirpichov
>            Assignee: Sean Owen
>              Labels: dot, dot-product, vector
>             Fix For: 0.6
>
>         Attachments: MAHOUT-823.patch
>
>
> http://codesearch.google.com/#6LK_nEANBKE/math/src/main/java/org/apache/mahout/math/RandomAccessSparseVector.java&l=172
> The complexity of the algorithm is O(num nondefault elements in this), while 
> it could clearly be O(min(num nondefault in this, num nondefault in x)).
> This can be fixed by adding this code before line 189.
> {code}
> if(x.getNumNondefaultElements() < this.getNumNondefaultElements()) {
>   return x.dot(this);
> }
> {code}
> An easy case where this asymmetry is very apparent and makes a huge 
> difference in performance is K-Means clustering.
> In K-Means for high-dimensional points (e.g. those that arise in text 
> retrieval problems), the centroids often have a huge number of non-zero 
> components, whereas points have a small number of them.
> So, if you make a mistake and use centroid.dot(point) in your code for 
> computing the distance, instead of point.dot(centroid), you end up with 
> orders of magnitude worse performance (which is what we actually observed - 
> the clustering time was a couple of minutes with this fix and over an hour 
> without it).
> So, perhaps, if you make this fix, quite a few people who had a similar case 
> but didn't notice it will suddenly have a dramatic performance increase :)

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