No ability to configure the JRE specified in generated .classpath file
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         Key: MPECLIPSE-100
         URL: http://jira.codehaus.org/browse/MPECLIPSE-100
     Project: maven-eclipse-plugin
        Type: Bug
    Versions: 1.9    
 Reporter: Ken Weiner
 Attachments: eclipse-plugin-patch.txt

The generated .classpath file always sets the JRE to the default JRE in Eclipse 
as follows:
 
<classpathentry kind="con"  path="org.eclipse.jdt.launching.JRE_CONTAINER"/>

There needs to be a way to override this so one can specify an alternate like 
so:

<classpathentry kind="con"  
path="org.eclipse.jdt.launching.JRE_CONTAINER/org.eclipse.jdt.internal.debug.ui.launcher.StandardVMType/sun-jdk-1.4.2.08"/>

In this case, the eclipse project would use the jdk that the user named 
"sun-jdk-1.4.2.08".

An easy way to fix this is to remove the hard-coded setting in plugin.jelly 
and, instead, make "org.eclipse.jdt.launching.JRE_CONTAINER" the default value 
of the "maven.eclipse.conclasspath" property.  Then in plugin.jelly, the 
<classpathentry kind="con"  path="..."/> would always be generated with a path 
equal to org.eclipse.jdt.launching.JRE_CONTAINER unless the property was 
overriden.

Carlos Sanchez helped me produce the patch.

An alternate fix would be to make a new property called something like 
"maven.eclipse.jre" which would have a value like "sun-jdk-1.4.2.08" in which 
case plugin.jelly would generate:

<classpathentry kind="con"  
path="org.eclipse.jdt.launching.JRE_CONTAINER/org.eclipse.jdt.internal.debug.ui.launcher.StandardVMType/sun-jdk-1.4.2.08"/>

instead of 

<classpathentry kind="con"  path="org.eclipse.jdt.launching.JRE_CONTAINER"/>

Attached are patches.

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