Trustin Lee <[EMAIL PROTECTED]> writes: > By doing this, all decoders will be free from the visibility > problem.
I missed the earlier part of this discussion. Does this mean that ProtocolDecoder.decode() calls will be synchronized to a particular decoder? That is, a given decoder instance will only be called on by one thread at a time? I thought we had discussed this earlier and confirmed that it was intentional that a decoder could be called on from multiple threads simultaneously. -- Steven E. Harris
