hi all,
Good to see 3.1 almost there. But I'm having some problem per the available
docs:
Can you review these? I tried both on Tomcat 5.5 and 6.0 (some notes below)
Configure OpenEJB per webapp requires the following steps:
Copy the openejb-loader-*.jar into the WEB-INF/lib directory of the webapp that
is
to use EJBs deployed onto OpenEJB
Add the loader servlet definition to the WEB-INF/web.xml file of the webapp
with a
valid value for openejb.home init-param.
<servlet>
<servlet-name>loader</servlet-name>
<servlet-class>org.openejb.loader.LoaderServlet</servlet-class>
<init-param>
<param-name>openejb.loader</param-name>
<param-value>tomcat-webapp</param-value>
</init-param>
<init-param>
<param-name>openejb.home</param-name>
<param-value>...define OPENEJB_HOME here...</param-value>
note: do we need openejb.home here?
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
Should you define other OpenEJB configuration settings use another <init-param>
stanza. It's just for that. These parameters are directly passed to OpenEJB at
initialization of the servlet. Think about the loader servlet as a bridge
between
OpenEJB's world (EJBs) and Tomcat's world (servlets, JSPs).
At startup OpenEJB prints out all of the configuration settings to Tomcat logs:
INFO: Installing web application at context path /openejb from URL
file:C:\webapps\openejb
OpenEJB init-params:
param-name: openejb.home, param-value: c:\openejb
param-name: openejb.configuration, param-value: conf\openejb.cfg
param-name: openejb.base, param-value:
c:\webapps\openejb\WEB-INF\openejb
param-name: openejb.loader, param-value: tomcat-webapp
Start up Tomcat and have fun with the EJBs
I looked at all the logs - no luck, do I also need to configure bean lookups? I
thought that was done automatically..
thanks,
Dario