I implemented the code, thanks.
At the beginning of the class I put this code:
Original Code
String aName( aEdtName.GetText() );
I've replaced with
::rtl::OUString aName2( aEdtName.GetText() );
The concatenation. This is fine
std::stringstream aS;
aS <<
"This"
<< ::rtl::OUStringToOString(aName2,
RTL_TEXTENCODING_ASCII_US).getStr()
<< std::endl;
I convert from stringstream to string
std::string s = aS.str();
_STL::cout << s;
Now I want to replace aName with s, in the following code fragment:
if (eCM != CM_RGB)
ConvertColorValues (aAktuellColor, CM_RGB);
pEntry = new XColorEntry( aAktuellColor, aName );
<---------------------- Original code
pEntry = new XColorEntry( aAktuellColor, s );
<----------------------
Would be like this
pColorTab->Insert( pColorTab->Count(), pEntry );
aLbColor.Append( pEntry );
aValSetColorTable.InsertItem( aValSetColorTable.GetItemCount() + 1,
pEntry->GetColor(), pEntry->GetName() );
aLbColor.SelectEntryPos( aLbColor.GetEntryCount() - 1 );
But this does not work, in building generates error:
http://imagebin.org/254616
It could be the type of variable?
How is the conversion from stringstream to string, is ok?
2013/4/18 Andre Fischer <[email protected]>
> On 18.04.2013 04:51, jorge ivan poot diaz wrote:
>
>> Hello,
>>
>> Thanks you, I have already changed the string as you said me. This is the
>> result:
>> ::rtl::OUString aName ( aEdtName.GetText() );
>>
>> And then I put this code
>>
>> std::stringstream aStrStream;
>> aStrStream << "\nThis is " << aName << " and " << aName << "
>> genial!" <<std::endl;
>> _STL::cout << aStrStream.str();
>>
>> The building was successful, but does not print whole aStrStream. Only
>> this
>> part:
>> This is
>> http://imagebin.org/254440
>>
>
> OUString is a UTF-16 string. That means that when it is created from an
> ASCII string then every second byte is '\0'. That means that
>
> aStrStream << "\nThis is " << aName << ...
>
> is basically equivalent to
>
> aStrStream << "\nThis is " << '\0' << ...
>
> Therfore everything after "\nThis is " is cut off. To fix this you have
> to replace
> << aName <<
>
> with
>
> << ::rtl::OUStringToOString(**aName, RTL_TEXTENCODING_ASCII_US).**getStr()
> <<
>
> You may want to use a small method to make this more readable:
>
> namespace
> {
> sal_Char* o2a (const ::rtl::OUString& rsText)
> {
> return ::rtl::OUStringToOString(**rsText,
> RTL_TEXTENCODING_ASCII_US).**getStr();
> }
> }
>
> and then
>
> aStrStream << "\nThis is " << o2a(aName) << ...
>
> [I did not compile this, there may be typos in this]
>
>
>
>
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