Hi,
Thanks for the quick response. I have further queries.
I tried to use DefaultHierarchyDataSource service. I was able to get
instance of the this service. According to the documentation, through it's
own XMultiServiceFactory interface implementation, I am trying to create the
instance of com.sun.star.ubp.HierarchyDataReadWriteAccess. It's not creating
the instance, even though it shows this service name in
getAvailableServiceNames() method. Am I doing something wrong? Do I need to
do something more to create an instance of
com.sun.star.ubp.HierarchyDataReadWriteAccess?
Below is my uno client code:
int SAL_CALL main(int argc, char **argv)
{
Reference< XSimpleRegistry > xReg = createSimpleRegistry();
if(!xReg.is())
{
cout<<"### cannot get service instance of
\"com.sun.star.regiystry.SimpleRegistry\"!\n";
exit(EXIT_FAILURE);
}
xReg->open(OUString::createFromAscii("./types.rdb"), sal_False,
sal_False);
if(!xReg->isValid())
{
cout<<"### cannot open test registry \"types.rdb\"!\n";
exit(EXIT_FAILURE);
}
Reference< XComponentContext > xContext =
bootstrap_InitialComponentContext(xReg);
if(!xContext.is())
{
cout<<"### cannot create intial component context!\n";
exit(EXIT_FAILURE);
}
Reference< XMultiComponentFactory > xMgr =
xContext->getServiceManager();
if(!xMgr.is())
{
cout<<"### cannot get initial service manager!\n";
exit(EXIT_FAILURE);
}
// get a HierarchyDataReadWriteAccess instance
Reference< XInterface > HierarchyDataSource ;
HierarchyDataSource =
xMgr->createInstanceWithContext(OUString::createFromAscii("com.sun.star.ucb.
DefaultHierarchyDataSource"), xContext);
if(!HierarchyDataSource.is())
{
cout<<"### cannot get service instance of
\"com.sun.star.ucb.DefaultHierarchyDataSource\"!\n";
exit(EXIT_FAILURE);
}
Reference< XMultiServiceFactory > xMSF( HierarchyDataSource, UNO_QUERY
);
if(!xMSF.is())
{
cout<<"### cannot get intetrface \"XMultiServiceFactory\"!\n";
exit(EXIT_FAILURE);
}
Sequence< OUString > supportedServiceNames =
xMSF->getAvailableServiceNames();
//Printing all supported services.
for( sal_Int32 serviceCount = 0 ; serviceCount <
supportedServiceNames.getLength() ; serviceCount ++ )
{
cout<<serviceCount+1<<". ";
cout<<OUStringToOString(supportedServiceNames.getConstArray()[serviceCount],
RTL_TEXTENCODING_ASCII_US).getStr();
cout<<endl;
}
Reference< XInterface > HieDataReadWriteAcc =
xMSF->createInstance(OUString::createFromAscii("com.sun.star.ucb.HierarchyDa
taReadWriteAccess"));
if(!HieDataReadWriteAcc.is())
{
cout<<"### cannot get service instance of
\"com.sun.star.ucb.HierarchyDataReadWriteAccess\"!\n";
exit(EXIT_FAILURE);
}
Reference< XNameContainer > xNC( HieDataReadWriteAcc, UNO_QUERY );
if(!xNC.is())
{
cout<<"### cannot get intetrface \"XNameContainer\"!\n";
exit(EXIT_FAILURE);
}
Reference< XComponent >::query( xContext )->dispose();
return 0;
}
Thanks and Regards,
Sunil
-----Original Message-----
From: Joerg Barfurth [mailto:[EMAIL PROTECTED]
Sent: Friday, April 08, 2005 7:38 PM
To: [email protected]
Subject: Re: [dev] Problem in accessing HierarchyDataReadWriteAccess
service
Hi Sunil,
Sunil Todi wrote:
> Hi,
>
> I am trying to find the implementations of HierarchyDataReadWriteAccess
> and HierarchyDataReadAccess services. I tried services.rdb but couldn't
> locate them there. Do I need to download them separately and register??
> Online documentation for these services can be found at
>
Hava a look at services HierarchyDataSource and DefaultHierarchyDataSource.
BTW: Services are abstract concepts, not concrete classes. Thus there
isn't necessarily *the* implementations of these services. For any given
service there may be any number of implementations. I am sure there are
some services defined in OOo IDL for which there are zero
implementations - but if there is an implementation of
DefaultHierarchyDataSource this probably isn't a case of that.
HTH, Joerg
--
Joerg Barfurth Sun Microsystems - Desktop - Hamburg
>>>>>>>>>>>>>>>>>> using std::disclaimer <<<<<<<<<<<<<<<<<<<<<<<
Software Engineer [EMAIL PROTECTED]
OpenOffice.org Configuration http://util.openoffice.org
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