On Sun, 17 Oct 2010, Stefan de Konink wrote:
message 'PrimitiveBlock': missing required field 'stringtable'
Error unpacking PrimitiveBlock message
(gdb) print *hmsg
$3 = {base = {descriptor = 0x406740, n_unknown_fields = 0,
unknown_fields = 0x0}, bbox = 0x0, n_required_features = 0,
required_features = 0x0, n_optional_features = 0, optional_features = 0x0,
writingprogram = 0x0, source = 0x0}
But lets look what is in the raw message:
(gdb) print bmsg.raw
$2 = {len = 56,
data = 0x60b550
"\n\032\b\276\210\360\350B\020\340\220\361\227g\030\236\226\305\344\370\002
\340\347\351\223\340\002\"\016OsmSchema-V0.6\"\nDenseNodes\201\n\002"}
Could it be an empty block?
(It missed a required feature)
If we look at one block after it, which the error actually has:
(gdb) print *bmsg
$1 = {base = {descriptor = 0x4057e0, n_unknown_fields = 0,
unknown_fields = 0x0}, has_raw = 1, raw = {len = 141264,
data = 0x7ffff7eaf010 "\n\261D\n"}, has_raw_size = 0, raw_size = 0,
has_zlib_data = 0, zlib_data = {len = 0, data = 0x0}, has_lzma_data = 0,
lzma_data = {len = 0, data = 0x0}, has_bzip2_data = 0, bzip2_data = {
len = 0, data = 0x0}}
The block has raw_size = 0 (that will result in badness!)
Now the question is? I'm trusting raw_size (because it is equal for
uncompress and compressed data) and it means the output size. I see that
you have only set 'len' of the raw message. While it is set in the
compressed case. Why is it 0?
Stefan
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