On Tue, Jun 18, 2013 at 01:11:22PM -0700, Ethan Jackson wrote:
> > In compose_output_action__(), the reason for the new test against
> > OVSP_NONE isn't clear to me.  Is this where we end up if a patch port
> > doesn't have a peer?  (How does it get OVSP_NONE?)
> 
> Right, all patch ports are initialized with OVSP_NONE.  If the patch
> port has a peer, it will be caught by the patch port implementation
> code.  Otherwise it will fall through and try to output to OVSP_NONE.

That's fine then, thanks.

Acked-by: Ben Pfaff <[email protected]>
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