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Christian Schoepplein schrieb:

>> my $SQL = "SELECT i.id, count( v.item_id ) AS votes, avg( v.rate ) AS
>> result".
>>
>> instead of:
>>
>> my $SQL = "SELECT i.id, count( v.item_id ) votes, avg( v.rate ) result".
>>
>> At least PostgreSQL will complain, otherwise.
> 
> Can you open a bug report on
> 
>     http://bugs.otrs.org
> 
> for this issue please? Our developers watch the bugzilla and the report 
> will not be lost.

the bug and the workaround is already known:

http://bugs.otrs.org/show_bug.cgi?id=1421

(and some duplicates)


regards, Torsten

- --
Torsten Thau, Dipl. Inform.
c.a.p.e. IT Labs GbR - Annaberger Str. 240 - D-09125 Chemnitz
phone: +49 371 5347 623
cell: +49 176 66 680 680
personal pgp-key: 0x93E0A174
fax: +49 371 5347 625
http://www.cape-it.de
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