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https://issues.apache.org/jira/browse/PDFBOX-1501?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Andreas Lehmkühler resolved PDFBOX-1501.
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Resolution: Fixed
Fix Version/s: 1.8.0
Assignee: Andreas Lehmkühler
I added the patch in revision 1441928 as proposed.
I added a debug output if an endChar command has more than 1 number as this
case shall not occur.
Thanks for the detailed report and the patch!
> Width of the character "201" .. inconsistent with the width in the PDF
> dictionary.
> ----------------------------------------------------------------------------------
>
> Key: PDFBOX-1501
> URL: https://issues.apache.org/jira/browse/PDFBOX-1501
> Project: PDFBox
> Issue Type: Bug
> Reporter: rahee ghurbhurn
> Assignee: Andreas Lehmkühler
> Fix For: 1.8.0
>
> Attachments: E-frutiger.pdf
>
>
> I have downloaded the trunk version of PDFBox for PDF/A validation purposes.
> The validation process fails with the following error :
> 3.1.6 : Invalid Font definition, Width of the character "201" in the font
> program "AEOQYB+Frutiger-Bold-ANSI"is inconsistent with the width in the PDF
> dictionary.
> The same PDF file is considered as valid when using Acrobat Pro X
> I used FontForge (as described in
> https://issues.apache.org/jira/browse/PDFBOX-1259) to check the width of the
> caracter and the value is correct 556. The same value is found in the PDF
> file.
> When running in debug mode I noticed that the CharStringRenderer constructor
> is called with "false" as parameter, meaning that the charString is not
> Type1 (Acrobat reader says it is Type1).
> When digging further, I found that in the handleCommandType2 method of
> CharStringRenderer does not update the width of the character because the
> following condition is not met
> else if ("endchar".equals(name)) {
> if (numbers.size() == 1 ) {
> setWidth(numbers.get(0));
> }
> }
> numbers has an array as value ([556, 171, 158, 69, 194]).
> In the handleSequence method of CharStringHandler, the sequence value used to
> compute the "numbers " value is [556, 171, 158, 69, 194, [14]]
> [14] being the endchar command.
> If I change the above condition to
> else if ("endchar".equals(name)) {
> if (numbers.size() % 2 == 1 ) {
> setWidth(numbers.get(0));
> }
> }
> The PDF file is considered as valid ... Is there a bug in the code or in the
> validation process or in the PDF file ?
> Why should there be a single character when the endchar command is met ?
> The the technical note 5177 (16 march 2000) issued by Adode says that the
> correct "sequence and form of a Type 2 charstring program may be represented
> as:
> w? {hs* vs* cm* hm* mt subpath}? {mt subpath}* endchar
> Where:
> w = width
> hs = hstem or hstemhm command
> vs = vstem or vstemhm command
> cm = cntrmask operator
> hm = hintmask operator
> mt = moveto (i.e. any of the moveto) operators
> subpath = refers to the construction of a subpath (one complete closed
> contour), which may include hintmask operators where appropriate.
> and the following symbols indicate specific usage:
> * zero or more occurrences are allowed
> ? zero or one occurrences are allowed
> + one or more occurrences are allowed
> { } indicates grouping
> The PDF file is attached to this mail and the Caracter 201 is Eacute.
> Thanks for your help
> Best regards
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