On Thu, 18 Sep 2003, Stas Bekman wrote:
> So did you look at the value of f->ctx before and after
> the apr_pcalloc() call on line 228 and that's when it has
> changed? are you sure that your compiler reports the line
> number correctly? Sometimes with an optimized code it may
> report wrong lines. e.g. I'd suggest to change:
> modperl_filter_t *filter =
> apr_pcalloc(p, sizeof(*filter));
>
> to:
>
> modperl_filter_t *filter;
> filter = apr_pcalloc(p, sizeof(*filter));
I find the same thing as Steve concerning this change:
within modperl_run_filter(), filter->f->ctx is null.
I hope I'm reading this right, but I tried the following.
Within modperl_output_filter_handler(), I had
....
else {
p = f->r ? f->r->pool : f->c->pool;
filter = modperl_filter_new(f, ....);
status = modperl_run_filter();
}
Just after the
p = f->r ? f->r->pool : f->c->pool;
line, p has a value 0x0142de30, f is 0x0142e548, and
f->ctx, f->r and f->c are all null. It then calls
modperl_filter_new(), within which I had
apr_pool_t *p;
modperl_filter_t *filter;
p = f->r ? f->r->pool : f->c->pool;
filter = (modperl_filter_t *)
apr_pcalloc(p, sizeof(modperl_filter_t));
At the line
p = f->r ? f->r->pool : f->c->pool;
p has a value 0x0142de30, f is 0x0142e548, and f->r and f->c
are null, all as before. After the call
filter = (modperl_filter_t *)
apr_pcalloc(p, sizeof(modperl_filter_t));
filter has a value 0x0142de30, which is the same as p
of before, and indeed filter->pool is 0x0142de30.
> > Does this help at all?
>
> Certainly. It is possible that the memory pool is messed
> up. If you change apr_pcalloc with apr_palloc does it
> still happen (if it doesn't it will crash elsewhere, since
> that just proves that apr_pcalloc allocates the already
> allocated memory). the next step would be to enable
> apr_pool debug tracing :(
I tried with apr_palloc, and, as you say, it crashes
earlier.
--
best regards,
randy
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