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https://issues.apache.org/jira/browse/PHOENIX-5176?page=com.atlassian.jira.plugin.system.issuetabpanels:all-tabpanel
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Lars Hofhansl resolved PHOENIX-5176.
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    Resolution: Fixed

Done. :)

> KeyRange.compareUpperRange(KeyRang 1, KeyRang 2) returns wrong result when 
> two key ranges have the same upper bound values but one is inclusive and 
> another is exclusive 
> -------------------------------------------------------------------------------------------------------------------------------------------------------------------------
>
>                 Key: PHOENIX-5176
>                 URL: https://issues.apache.org/jira/browse/PHOENIX-5176
>             Project: Phoenix
>          Issue Type: Bug
>            Reporter: Bin Shi
>            Assignee: Bin Shi
>            Priority: Blocker
>             Fix For: 4.15.0, 5.1.0
>
>          Time Spent: 4h
>  Remaining Estimate: 0h
>
> In KeyRange.java, 
> {color:#262626}    public static int compareUpperRange(KeyRange rowKeyRange1, 
> KeyRange rowKeyRange2) {{color}
> {color:#262626}        int result = 
> Boolean.compare(rowKeyRange1.upperUnbound(), 
> rowKeyRange2.upperUnbound());{color}
> {color:#262626}        if (result != 0) {{color}
> {color:#262626}            return result;{color}
> {color:#262626}        }{color}
> {color:#262626}        result = 
> Bytes.BYTES_COMPARATOR.compare(rowKeyRange1.getUpperRange(), 
> rowKeyRange2.getUpperRange());{color}
> {color:#262626}        if (result != 0) {{color}
> {color:#262626}            return result;{color}
> {color:#262626}        }{color}
> {color:#262626}        return 
> Boolean.compare(*rowKeyRange2*.isUpperInclusive(), 
> *rowKeyRange1*.isUpperInclusive());{color}
> {color:#262626}    }{color}
> {color:#262626} {color}
> {color:#262626}The last line in yellow color should be "{color}return 
> Boolean.compare(*rowKeyRange1*.isUpperInclusive(), 
> *rowKeyRange2*.isUpperInclusive());".  Given rowKeyRange1 [3, 5) and 
> rowKeyRange2 [3, 5], the function should return -1, but now it returns 1 due 
> to the bug I mentioned.
>  
> The KeyRange.compareUpperRange is only used in 
> KeyRange.intersect(List<KeyRange> rowKeyRanges1, List<KeyRange> 
> rowKeyRanges2). Given rowKeyRanges1 \{[3, 5), [5, 6)} and rowKeyRanges2\{[3, 
> 5], [6, 7]}, the function should return \{[3, 5), [5, 5]}, i.e., \{[3, 5]}, 
> but it seems that now it returns \{[3,5)} due to the bug.



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