https://issues.apache.org/bugzilla/show_bug.cgi?id=49222
Summary: Cant read odt file created in both OpenOffice 3.2 and
MicrosoftOffice2007
Product: POI
Version: 3.6
Platform: PC
OS/Version: Windows XP
Status: NEW
Severity: normal
Priority: P2
Component: XWPF
AssignedTo: [email protected]
ReportedBy: [email protected]
When I try to open odt file poi throws Exception as follows:
Exception in thread "main" org.apache.poi.POIXMLException:
org.apache.poi.openxml4j.exceptions.InvalidFormatException: Package should
contain a content type part [M1.13]
at org.apache.poi.util.PackageHelper.open(PackageHelper.java:55)
at org.apache.poi.xwpf.usermodel.XWPFDocument.<init>(XWPFDocument.java:98)
at pl.macio.WordGenerator.generate(WordGenerator.java:109)
at pl.macio.WordGenerator.main(WordGenerator.java:87)
Caused by: org.apache.poi.openxml4j.exceptions.InvalidFormatException: Package
should contain a content type part [M1.13]
at
org.apache.poi.openxml4j.opc.ZipPackage.getPartsImpl(ZipPackage.java:147)
at org.apache.poi.openxml4j.opc.OPCPackage.getParts(OPCPackage.java:585)
at org.apache.poi.openxml4j.opc.OPCPackage.open(OPCPackage.java:201)
at org.apache.poi.openxml4j.opc.OPCPackage.open(OPCPackage.java:178)
at org.apache.poi.util.PackageHelper.open(PackageHelper.java:53)
... 3 more
WordGenerator is my class in which I try to open some odt file:
line 108 is: InputStream fis = new FileInputStream(inFileName);
line 109 is: XWPFDocument doc = new XWPFDocument(fis);
This exception is thrown in fact by ZipPackage.getPartsImpl().
As this method is looking for entry with name ("[Content_Types].xml" -
ContentTypeManager.CONTENT_TYPES_PART_NAME), but in files stored in both
OpenOffice and MSOffice there is nothing like this.
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