Hi, I m using apache poi 3.7 jar and was stuck at one place while designing the functionality, would require expert guidance on same.
I am reading excel using foll sample code workbook = WorkbookFactory.create(new FileInputStream(fileName)); After getting org.apache.poi.ss.usermodel.Workbook object ,i get org.apache.poi.ss.usermodel.Sheet object and i pass it some method where i can apply logic. All above works fine. During processing logic if there is any erroneous condition matched i need to show user a message with excel file name or excel file path. Now i need to retrieve excel file name or excel file path using org.apache.poi.ss.usermodel.Sheet object as within the method i have access only to Sheet object . Is there any way to retrieve the same using Sheet object ,i had gone through org.apache.poi.ss.usermodel.Sheet class and was able to retrieve workbook object using Sheet class getWorkbook object but was not able to find a way to get Excel file name or excel file path. Thanks in advance. -- View this message in context: http://apache-poi.1045710.n5.nabble.com/Retrieve-Excel-File-name-path-using-Sheet-object-tp4932272p4932272.html Sent from the POI - Dev mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: dev-unsubscr...@poi.apache.org For additional commands, e-mail: dev-h...@poi.apache.org
