Thanks Alan, that explains it.

-----Original Message-----
From: Alan Conway [mailto:[email protected]] 
Sent: 11 March 2009 14:41
To: [email protected]
Subject: Re: questions about the c++ failover example program

Shan Wang wrote:
> Hi All,
> 
>  
> 
> I'm a bit confused about the c++ failover example replay_sender and
> resume_receiver. What kind of exchange are they using?
> 
> In the declare_queue.cpp in examples/failover, it only uses the
> following line to declare the queue:
> 
>  
> 
> session.queueDeclare(arg::queue="message_queue");
> 
>  
> 
> There are no routing_key bindings for this queue. And in
> replay_sender.cpp, sender sets routing_key the same as the queue name:
> 
>  
> 
> message.getDeliveryProperties().setRoutingKey(queue);
> 
>  
> 
> here queue is "message_queue". In resume_receiver.cpp, listener
> subscribes to the queue directly:
> 
>  
> 
> subscription = subs.subscribe(*this, "message_queue");
> 
>  
> 
> So do failover sender and receiver use any kind of exchange? Will the
> direct/fanout/topic exchange code work on failover connections?

Yes, they do. AMQP specifies that every broker has a default "nameless" 
exchange. This exchange is a direct exchange. When queues are created
they are 
automatically bound to this exchange by their name.

So you can send to any queue by using the empty string as an exchange
name and 
the queue name as routing key. This applies in general, its not specific
to 
failover.

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