What should be the result of (take 0 "nonlist") In the spirit of this bug report, I think it should be an error http://bugs.racket-lang.org/query/?cmd=view&pr=11458
But right now it evaluates to the empty list. On Wed, Jan 26, 2011 at 6:43 PM, Stephen Chang <stch...@ccs.neu.edu> wrote: > Oh sorry, didnt read carefully. I now see that it wasnt my push you > were replying to. > > > > On Wed, Jan 26, 2011 at 6:42 PM, Stephen Chang <stch...@ccs.neu.edu> wrote: >> That wasnt the bug that I was fixing. >> >> >> >> On Wed, Jan 26, 2011 at 5:58 PM, Matthew Flatt <mfl...@cs.utah.edu> wrote: >>> At Wed, 26 Jan 2011 17:07:32 -0500, e...@racket-lang.org wrote: >>>> + (let ([n0 (! n)]) >>>> + (unless (exact-nonnegative-integer? n) >>>> + (raise-type-error 'take "non-negative exact integer" 0 n l)) >>> >>> Still committing changes with no tests. >>> >>> Still broken: >>> >>> > (list-ref (take (car (list 1)) (list 2)) 0) >>> take: expects type <non-negative exact integer> as 1st argument, given: >>> #<promise!1>; other arguments were: '(2) >>> >>> _________________________________________________ >>> For list-related administrative tasks: >>> http://lists.racket-lang.org/listinfo/dev >>> >> > _________________________________________________ For list-related administrative tasks: http://lists.racket-lang.org/listinfo/dev
