Does that mean that I can/should just drop the .1 to get the defined name? Can it also be .2 etc?
Sam On Jul 16, 2014 4:34 AM, "Matthew Flatt" <mfl...@cs.utah.edu> wrote: > That `posn1.1` is a unreadable symbol that stands for the symbol > `posn1` plus some marks that distinguish it. > > In other words, `posn1.1` bridges (in an ugly way) the symbol-based > world of module environments and the identifier-based world of syntax. > In the future, I hope to shift module environments to be > identifier-based to avoid these unreadable symbols. > > At Tue, 15 Jul 2014 09:10:26 -0400, Sam Tobin-Hochstadt wrote: > > If you take this program and fully-expand it in the macro stepper: > > > > #lang racket > > (struct posn (x y)) > > (define p1 (posn 1 2)) > > > > You see that the residual program has an application of the `posn1` > > function, which is the hidden constructor. And indeed, the > > fully-expanded program has a definition of `posn1`. However, if you > > click on the use of `posn1`, the macro stepper will tell you that it's > > defined in this module as `posn1.1`, and provided as `posn1.1` as > > well. If you write program to grovel through the fully-expanded > > syntax, you get these same results as the `src-id` and > > `nominal-src-id` from `identifier-binding`. > > > > Why is this? And is there a way to get from `posn1.1` to `posn1` > reliably? > > > > Sam >
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