Hi all, I am using Spark 1.3.1 to write a Spectral Clustering algorithm. This really confused me today. At first I thought my implementation is wrong. It turns out it's an issue in MLlib. Fortunately, I've figured it out.
I suggest to add a hint on user document of MLlib ( as far as I know, there have not been such hints yet) that indices of Local Sparse Vector must be ordered in ascending manner. Because of ignorance of this point, I spent a lot of time looking for reasons why computeSVD of RowMatrix did not run correctly on Sparse data. I don't know the influence of Sparse Vector without ordered indices on other functions, but I believe it is necessary to let the users know or fix it. Actually, it's very easy to fix. Just add a sortBy function in internal construction of SparseVector. Here is an example to reproduce the affect of unordered Sparse Vector on computeSVD. ================================================ //in spark-shell, Spark 1.3.1 import org.apache.spark.mllib.linalg.distributed.RowMatrix import org.apache.spark.mllib.linalg.{SparseVector, DenseVector, Vector, Vectors} val sparseData_ordered = Seq( Vectors.sparse(3, Array(1, 2), Array(1.0, 2.0)), Vectors.sparse(3, Array(0,1,2), Array(3.0, 4.0, 5.0)), Vectors.sparse(3, Array(0,1,2), Array(6.0, 7.0, 8.0)), Vectors.sparse(3, Array(0,2), Array(9.0, 1.0)) ) val sparseMat_ordered = new RowMatrix(sc.parallelize(sparseData_ordered, 2)) val sparseData_not_ordered = Seq( Vectors.sparse(3, Array(1, 2), Array(1.0, 2.0)), Vectors.sparse(3, Array(2,1,0), Array(5.0,4.0,3.0)), Vectors.sparse(3, Array(0,1,2), Array(6.0, 7.0, 8.0)), Vectors.sparse(3, Array(2,0), Array(1.0,9.0)) ) val sparseMat_not_ordered = new RowMatrix(sc.parallelize(sparseData_not_ordered, 2)) //apparently, sparseMat_ordered and sparseMat_not_ordered are essentially the same matirx //however, the computeSVD result of these two matrixes are different. Users should be notified about this situation. println(sparseMat_ordered.computeSVD(2, true).U.rows.collect.mkString("\n")) println("===================") println(sparseMat_not_ordered.computeSVD(2, true).U.rows.collect.mkString("\n")) ====================================================== The results are: ordered: [-0.10972870132786407,-0.18850811494220537] [-0.44712472003608356,-0.24828866611663725] [-0.784520738744303,-0.3080692172910691] [-0.4154110101064339,0.8988385762953358] not ordered: [-0.10830447119599484,-0.1559341848984378] [-0.4522713511277327,-0.23449829541447448] [-0.7962382310594706,-0.3130624059305111] [-0.43131320303494614,0.8453864703362308] Looking into this issue, I can see it's reason locates in RowMatrix.scala(line 629). The implementation of Sparse dspr here requires ordered indices. Because it is scanning the indices consecutively to skip empty columns. ----- Feel the sparking Spark! -- View this message in context: http://apache-spark-developers-list.1001551.n3.nabble.com/Indices-of-SparseVector-must-be-ordered-while-computing-SVD-tp11731.html Sent from the Apache Spark Developers List mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: dev-unsubscr...@spark.apache.org For additional commands, e-mail: dev-h...@spark.apache.org