Change for submitting to yarn in 1.3.1

[Ron's Yahoo!]

Hi,
  I used to submit my Spark yarn applications by using 
org.apache.spark.yarn.deploy.Client api so I can get the application id after I 
submit it. The following is the code that I have, but after upgrading to 1.3.1, 
the yarn Client class was made into a private class. Is there a particular 
reason why this Client class was made private?
  I know that there’s a new SparkSubmit object that can be used, but it’s not 
clear to me how I can use it to get the application id after submitting to the 
cluster.
  Thoughts?

Thanks,
Ron

class SparkLauncherServiceImpl extends SparkLauncherService {
  
  override def runApp(conf: Configuration, appName: String, queue: String): 
ApplicationId = {
    val ws = SparkLauncherServiceImpl.getWorkspace()
    val params = Array("--class", //
        "com.xyz.sparkdb.service.impl.AssemblyServiceImpl", //
        "--name", appName, //
        "--queue", queue, //
        "--driver-memory", "1024m", //
        "--addJars", 
getListOfDependencyJars(s"$ws/ledp/le-sparkdb/target/dependency"), //
        "--jar", 
s"file:$ws/ledp/le-sparkdb/target/le-sparkdb-1.0.3-SNAPSHOT.jar")
    System.setProperty("SPARK_YARN_MODE", "true")
    System.setProperty("spark.driver.extraJavaOptions", "-XX:PermSize=128m 
-XX:MaxPermSize=128m -Dsun.io.serialization.extendedDebugInfo=true")
    val sparkConf = new SparkConf()
    val args = new ClientArguments(params, sparkConf)
    new Client(args, conf, sparkConf).runApp()
  }
  
  private def getListOfDependencyJars(baseDir: String): String = {
    val files = new 
File(baseDir).listFiles().filter(!_.getName().startsWith("spark-assembly"))
    val prependedFiles = files.map(x => "file:" + x.getAbsolutePath())
    val result = ((prependedFiles.tail.foldLeft(new 
StringBuilder(prependedFiles.head))) {(acc, e) => acc.append(", 
").append(e)}).toString()
    result
  }
}