Andrew, you're correct of course hashing is a one-way operation with
potential collisions

On Wed, Sep 21, 2016 at 3:22 PM, Andrew Duffy <r...@aduffy.org> wrote:
> Pedantic note about hashCode and equals: the equality doesn't need to be
> bidirectional, you just need to ensure that a.hashCode == b.hashCode when
> a.equals(b), the bidirectional case is usually harder to satisfy due to
> possibility of collisions.
>
> Good info:
> http://www.programcreek.com/2011/07/java-equals-and-hashcode-contract/
> _____________________________
> From: Jakob Odersky <ja...@odersky.com>
> Sent: Wednesday, September 21, 2016 15:12
> Subject: Re: What's the use of RangePartitioner.hashCode
> To: WangJianfei <wangjianfe...@otcaix.iscas.ac.cn>
> Cc: dev <dev@spark.apache.org>
>
>
>
> Hi,
> It is used jointly with a custom implementation of the `equals`
> method. In Scala, you can override the `equals` method to change the
> behaviour of `==` comparison. On example of this would be to compare
> classes based on their parameter values (i.e. what case classes do).
> Partitioners aren't case classes however it makes sense to have a
> value comparison between them (see RDD.subtract for an example) and
> hence they redefine the equals method.
> When redefining an equals method, it is good practice to also redefine
> the hashCode method so that `a == b` iff `a.hashCode == b.hashCode`
> (e.g. this is useful when your objects will be stored in a hash map).
> You can learn more about redefining the equals method and hashcodes
> here
> https://www.safaribooksonline.com/library/view/scala-cookbook/9781449340292/ch04s16.html
>
>
> regards,
> --Jakob
>
> On Thu, Sep 15, 2016 at 6:17 PM, WangJianfei
> <wangjianfe...@otcaix.iscas.ac.cn> wrote:
>> who can give me an example of the use of RangePartitioner.hashCode, thank
>> you!
>>
>>
>>
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>>
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