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https://issues.apache.org/jira/browse/SQOOP-489?page=com.atlassian.jira.plugin.system.issuetabpanels:comment-tabpanel&focusedCommentId=13283168#comment-13283168
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Jarek Jarcec Cecho commented on SQOOP-489:
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I wasn't checking sources so I might be wrong here. But let me explain what I
was afraid of on example:
Imagine table with three columns A, B, C with one row - 1, 2, 3. User specify
that A should be used as partitioned column. Then after applying suggested fix
we will create following create table statement:
CREATE TABLE IF NOT EXISTS `FOO` (`B` STRING, `C` STRING) PARTITIONED BY (A
STRING)
But sqoop import will by default import all columns and thus resulting in file
"1, 2, 3". Now when hive will read the file column B will contain value 1 (e.g.
value of A), column C will contain value 2 (value of column B) and value 3 for
column C will be missing entirely from hive perspective. Again I did no
research nor try it in practice. It's solely based on my experience and I
wanted to express my worries prior any coding.
Is it more clear now?
Jarcec
> Cannot define partition keys for Hive tables created through Sqoop
> ------------------------------------------------------------------
>
> Key: SQOOP-489
> URL: https://issues.apache.org/jira/browse/SQOOP-489
> Project: Sqoop
> Issue Type: Bug
> Affects Versions: 1.4.1-incubating
> Reporter: Kathleen Ting
> Attachments: SQOOP-489.patch
>
>
> By enabling the table option, Sqoop includes every column in the table in the
> create table query, and by enabling the hive-partition-key option, Sqoop
> blindly appends the "partitioned by" clause. Now if you specify one of
> columns in the table in the hive-partition-key, this will cause a syntax
> error in Hive.
> For example, if we have a table 'FOO' that has columns 'I' and 'J':
> sqoop create-hive-table --table FOO ...
> will generate the following Hive query:
> CREATE TABLE IF NOT EXISTS `FOO` ( `I` STRING, `J` STRING)
> Now if we add "--hive-partition-key I" to the command, Sqoop generates the
> following query:
> CREATE TABLE IF NOT EXISTS `FOO` ( `I` STRING, `J` STRING) PARTITIONED BY (I
> STRING)
> The problem is that since 'I' is defined twice (once in CRATE TABLE and once
> in PARTITIONED BY), this is a syntax error in Hive.
> This correct query would be something like:
> CREATE TABLE IF NOT EXISTS `FOO` (`J` STRING) PARTITIONED BY (I STRING)
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