Travis Vitek wrote:
Eric Lemings wrote:
What is the default BUILDTYPE if it is not defined in the build (make)
command?
11s
Not quite. The default build type is no optimization (no -O),
no debugging (no -g), and no reentrancy. There's no numeric
mnemonic for it.
Martin
Here are some values from $builddir/makefile.in when BUILDTYPE is not
specified:
CONFIG_H = gcc-4.1.1-
BUILDTYPE =
BUILDMODE =
LIBBASE = std$(BUILDTYPE)
Are these values correct?
I haven't looked but do the docs say if BUILDTYPE (or BUILDMODE) is
required?
From section 5 of the README
Note that exactly one of BUILDTYPE and BUILDMODE must be
defined.
This comment is not totally accurate from a user perspective. They are
allowed to provide neither as indicated by the quote pasted below...
Or what the default is?
Again, from section 5 of the README
The <build-type> argument is optional. When not
specified a build type of 11s is assumed.
If there isn't a default, I think we should establish one: shared,
reentrant in all snapshots (i.e. all development) and release on
all systems, wide builds on wide systems in snapshots and releases
that support them, debug in snapshots, and optimized in releases.
I only followed that sentence for the first 20 words or so. I don't
understand what you mean when you refer to 'snapshots' and 'releases'.
It sounds like you are proposing that the default be different based on
who is doing the build?
Thanks,
Brad.
