yes, this is because the parfor optimizer overwrites this specification. You could use either one of the following 1) "parfor(opt=NONE, par=1)" (disables optimization, uses defaults, and overwrites the specified parameters) 2) "parfor(opt=CONSTRAINED, par=1)" (optimizes as usual under the constraint of the specified parameters) 3) for() (since parfor is derived from for, you can always use for wherever you can use parfor, useful for debugging)
Regards, Matthias From: Deron Eriksson <[email protected]> To: [email protected] Date: 02/12/2016 12:10 PM Subject: Turn off parallelism in parfor? Hi, Is it possible to turn off parallelism in a parfor loop using a function parameter? I tried setting 'par' to 1. If I print i in a for loop, the results come back in order: for (i in 1:5) { print(i) } gives 1 2 3 4 5 If I print i in a parfor loop (with par=1), the results don't come back in order: parfor (i in 1:5, par=1) { print(i) } gives (something similar to) 4 2 5 1 3 Is par=1 (I tried par=0 too) turning off parallelism but the print output isn't reflecting that? Deron
