Github user okram commented on a diff in the pull request:
https://github.com/apache/tinkerpop/pull/524#discussion_r95001231
--- Diff:
spark-gremlin/src/test/java/org/apache/tinkerpop/gremlin/spark/process/computer/traversal/strategy/optimization/SparkInterceptorStrategyTest.java
---
@@ -142,7 +142,7 @@ public void
shouldSuccessfullyEvaluateInterceptedTraversals() throws Exception {
test(6l, g.V().out().values("name").count());
test(2l, g.V().out("knows").values("name").count());
test(3l, g.V().in().has("name", "marko").count());
- test(6l, g.V().repeat(__.dedup()).times(2).count());
+ test(0l, g.V().repeat(__.dedup()).times(2).count());
--- End diff --
This is crazy. The right answer is `0`. Think about it. It goes through
once, fine, all 6 vertices. The second time -- already seem them! Filter. Thus,
0.
However, I just checked OLTP and it assumes 6. Wondering what is "right" ?.
....
```
gremlin> g = TinkerFactory.createModern().traversal()
==>graphtraversalsource[tinkergraph[vertices:6 edges:6], standard]
gremlin> g.V().repeat(dedup()).times(2)
==>v[1]
==>v[2]
==>v[3]
==>v[4]
==>v[5]
==>v[6]
gremlin> g.withComputer().V().repeat(dedup()).times(2)
gremlin>
```
Whatever, is decided as the correct answer, we should definitely put this
into `RepeatTest`. I just randomly had this query in a Spark test.
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