Github user mpollmeier commented on the issue:
https://github.com/apache/tinkerpop/pull/606
In theory, yes. But it seems to behave fine as it is. Here's a scenario for
the gremlin-groovy shell:
```
g = TinkerGraph.open()
v0 = g.addVertex("x", 1)
v1 = g.addVertex("x", 2)
v2 = g.addVertex("x", 2)
v0.addEdge("edge", v1)
v1.addEdge("edge", v2)
g.traversal().V(v0.id).repeat(out()).until(has("x", 2)).path()
```
If `until` would incorrectly behave like `emit`, I would assume that we'd
see all three nodes in the path. Instead we only see v0 and v1, which is the
correct behavious for repeat/until. Is our scenario missing something?
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