https://issues.apache.org/bugzilla/show_bug.cgi?id=56573
--- Comment #4 from Konstantin Kolinko <knst.koli...@gmail.com> --- HttpServletRequest.getRequestURI(): http://docs.oracle.com/javaee/7/api/javax/servlet/http/HttpServletRequest.html#getRequestURI%28%29 Session.getRequestURI() http://docs.oracle.com/javaee/7/api/javax/websocket/Session.html#getRequestURI%28%29 The WebSocket method is clearly documented to include a query string (as opposed to HttpServletRequest method). It also returns an URI, not a String. These are different methods. Personally, it is not clear to me from WebSocket documentation whether this method includes a contextPath, not saying about protocol, server name and port. It is also not clear whether it is "decoded" or non-decoded path (see Servlet API method), but as it is an URI maybe it does not matter. -- You are receiving this mail because: You are the assignee for the bug. --------------------------------------------------------------------- To unsubscribe, e-mail: dev-unsubscr...@tomcat.apache.org For additional commands, e-mail: dev-h...@tomcat.apache.org
