hello,when I run usergrid-rest
 access link:http://localhost:8080/usergrid-rest/status
 
response:
 
{
 "error": "uncaught", "timestamp": 1445572529016, "duration": 119, "exception": 
"org.apache.usergrid.rest.exceptions.UncaughtException", "error_description": 
"Internal Server Error", "error_id": "e664f258-7939-11e5-954f-a41731054ba5"  
}
 
console error:
 
2015-10-23 11:48:08,110 ERROR  
(Notifications_Processor026b090c-7518-417a-b0c9-0bfd6b036866)  
[org.apache.usergrid.services.ServiceManager] - Failed to get  application
 java.lang.RuntimeException: application id 
{b6768a08-b5d5-11e3-a495-11ddb1de66c8} is returning null
     at 
org.apache.usergrid.services.ServiceManager.init(ServiceManager.java:103)
     at 
org.apache.usergrid.services.ServiceManagerFactory.getServiceManager(ServiceManagerFactory.java:69)
     at 
org.apache.usergrid.services.notifications.QueueListener.execute(QueueListener.java:147)
     at 
org.apache.usergrid.services.notifications.QueueListener.access$0(QueueListener.java:137)
     at 
org.apache.usergrid.services.notifications.QueueListener$1.run(QueueListener.java:123)
     at java.util.concurrent.Executors$RunnableAdapter.call(Unknown Source)
     at java.util.concurrent.FutureTask.run(Unknown Source)
     at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
     at java.util.concurrent.ThreadPoolExecuto
 
Environment:
 
usergrid :     2.1 release 
 cassandra :  apache-cassandra-2.1.8
 web server:  tomcat 7
 
uuid define:
 
i find this define on org.apache.usergrid.corepersistence.util.CpNamingUtils,
 public static final UUID MANAGEMENT_APPLICATION_ID = UUID.fromString( 
"b6768a08-b5d5-11e3-a495-11ddb1de66c8" );
 
other:
 
if has demo cql for cassandra,can you tell me ? I create cassandra keyspaces 
like usergrid docs,but error is alwith appear.
 this error probably I missing column family data,but I try more times ,but No 
solution,so I Seek help,hope get you help,thanks.

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