Hanks10100 closed pull request #191: Update broadcast-channel.md
URL: https://github.com/apache/incubator-weex-site/pull/191
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diff --git a/source/cn/references/broadcast-channel.md
b/source/cn/references/broadcast-channel.md
index d626a85ae..3794025a2 100644
--- a/source/cn/references/broadcast-channel.md
+++ b/source/cn/references/broadcast-channel.md
@@ -75,16 +75,16 @@ const Hulk = new BroadcastChannel('Avengers')
在页面 C 中：
```js
-const Stack = new BroadcastChannel('Avengers')
-Stack.onmessage = function (event) {
+const Stark = new BroadcastChannel('Avengers')
+Stark.onmessage = function (event) {
console.log(event.data) // Assemble!
- Stack.postMessage('I am Tony and I am leaving now.')
+ Stark.postMessage('I am Tony and I am leaving now.')
}
```
页面 A 、B 、C 都创建一个监听了 `'Avengers'` 频道的 BroadcastChannel 对象，它们可以用这个对象实现互相通信。
-当 Steve 发布了 `'Assemble!'` 消息时，Stack 将收到一个消息事件，其 `data` 字段等于
`'Assemble!'`，然后也向频道中回复一条消息。但是 Hulk 并不会收到这些消息，因为他没有实现`onmessage`
方法，相当于没有接收频道中的消息，所以他实际上不是一个订阅者。
+当 Steve 发布了 `'Assemble!'` 消息时，Stark 将收到一个消息事件，其 `data` 字段等于
`'Assemble!'`，然后也向频道中回复一条消息。但是 Hulk 并不会收到这些消息，因为他没有实现`onmessage`
方法，相当于没有接收频道中的消息，所以他实际上不是一个订阅者。
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