Alexandr Klimov created XMLSCHEMA-29:
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Summary: An element without "ref" and "type" attributes has not
got any assigned XSD type but should has got "anyType" XSD type.
Key: XMLSCHEMA-29
URL: https://issues.apache.org/jira/browse/XMLSCHEMA-29
Project: XmlSchema
Issue Type: Bug
Affects Versions: 2.0.2
Reporter: Alexandr Klimov
I faced with some trouble when I have tried parse following XSD:
{code:xml}
<?xml version="1.0"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema";
targetNamespace="http://www.w3schools.com";
xmlns="http://www.w3schools.com";>
<xs:complexType name="TestType">
<xs:sequence>
<xs:element name="stringElem" type="xs:string"/>
<xs:element name="dummyElem"/>
</xs:sequence>
</xs:complexType>
</xs:schema>
{code}
A XmlSchemaElement object corresponds to *dummyElem* element has got
*schemaType* and *schemaTypeName* fields equal *NULL*.
But I'm convinced that in this case
{noformat}{http://www.w3.org/2001/XMLSchema}anyType{noformat} type should be
assigned as type of the untyped element. My point of view based on following
document: [W3C XML Schema Definition Language 1.1 |
http://www.w3.org/TR/xmlschema11-1/], point 3.3.2.1
This *anyType* type is defined in
*org.apache.ws.commons.schema.constants.Constants* class but I have not found
where it is used in any assignment during XSD parsing.
In my opinion,
*org.apache.ws.commons.schema.SchemaBuilder#handleElementGlobalType* method
should contains the third condition branch for a case when *type* and *ref*
attributes are absent and *anyType* type should be set in the branch.
May be I misunderstand something in a XSD definition and *anyType* type can not
be assigned in this case?
Best regards
Alexandr Klimov.
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