Fixed. It was not a problem with parseInt method. It was a problem with print() operation in jaggery. Even if I run "print(1)" it prints "1.0". Easy fix is to enter print(i+"") instead print(i) which converts the integer into a string.
Thanks Dimuthu On Sun, Feb 9, 2014 at 5:23 PM, Dimuthu Upeksha <[email protected]> wrote: > Hi all, > In this simple jaggery code > > for(var i=0;i<10;i++){ > > print(i); > > print("<br/>"); > > } > > Output was like > > 0.0 > > 1.0 > > .... > > I need to parse these outputs into integer. I tried parseInt(i) method but > it also gave the same result. What could be the reason for that? > > Thanks > > Dimuthu > > -- > Dimuthu Upeksha > Engineering Intern > WSO2 inc. > -- Dimuthu Upeksha Engineering Intern WSO2 inc.
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