Thanks Kasun. we will look into this.
On Thu, Jul 10, 2014 at 5:13 PM, Kasun Gajasinghe <[email protected]> wrote: > > If you need to get the webapp details of a particular webapp, then you > need to call WebappAdmin#getStartedWebapp method. You are currently > calling getPagedWebappsSummary which returns an array of webapp data > (wrapped in a WebappsWrapper object) according to the webappSearchString > you use. > > Regards, > KasunG > > > On Thu, Jul 10, 2014 at 5:00 PM, Dimuthu De Lanerolle <[email protected]> > wrote: > >> I noticed while retrieving the webapp information by invoking the Web app >> admin service client (WebAppAdminClient class getWebAppInfo(..)) , it >> throws " java.rmi.RemoteException: More than one service found with the >> given name" exception. >> It seems like this happens due to two distinct JaggeryWebApps ( >> productapipublisher and publisher) hosted in the same EMM server and when >> we try to retrieve web info of the publisher Jaggery WebApp. >> >> If the main reason causing this exception is because there are more than >> one service available with the given web app name prefix what could be the >> best possible solution to solve this issue? >> >> Regards >> >> >> -- >> Dimuthu De Lanerolle >> Software Engineer >> WSO2 Inc. >> lean . enterprise . middlewear. >> http://wso2.com/ >> Tel. : +94 11 2145345 Fax : +94 11 2145300 email : [email protected] >> >> > > > -- > > *Kasun Gajasinghe*Senior Software Engineer, WSO2 Inc. > email: kasung AT spamfree wso2.com > linked-in: http://lk.linkedin.com/in/gajasinghe > blog: http://kasunbg.org > > > -- Dimuthu De Lanerolle Software Engineer WSO2 Inc. lean . enterprise . middlewear. http://wso2.com/ Tel. : +94 11 2145345 Fax : +94 11 2145300 email : [email protected]
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