After looking further into this issue, in java6 the default stack size is not different between Linux and Windows but between 32bit and 64bit implementations. This explains a lot as we're using 64bit linux. I can't find what the default stack sizes were in java5 though. I guess I'll just have to add a -Xss parameter to my application although this doesn't fill me with confidence, "Options that begin with -X are non-standard (not guaranteed to be supported on all VM implementations), and are subject to change without notice in subsequent releases of the JDK." - http://java.sun.com/javase/technologies/hotspot/vmoptions.jsp

Chris wrote:
I have come across a repeatable error and enclose the test case.
When the following xml is validated with a ValidatingStreamReader it causes an SOE. If the sample string is shorter, this does not happen. With more complex schemas, the string does not have to be as long to still cause an SOE. I have not yet determined whether the complexity of the pattern is a factor. Increasing the size of the stack using "java -Xss64M" does prevent this issue.

This only happens in Windows, Linux does not have this behaviour. This does not happen on any platform in java 5.

Note there were changes in java6 to the way stack sizes are implemented.
http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=6316197

I'm not sure if this is really a bug in xmlbeans since it does work on other platforms... is there any reason why it would use more stack space on windows? Is the default stack size different on windows and linux?

Thanks for your help

See stack trace below:
org.apache.xmlbeans.impl.regex.RangeToken.match(line 481)
org.apache.xmlbeans.impl.regex.RegularExpression.matchString(line 1673)
org.apache.xmlbeans.impl.regex.RegularExpression.matchString(line 1872)
org.apache.xmlbeans.impl.regex.RegularExpression.matchString(line 1872)
org.apache.xmlbeans.impl.regex.RegularExpression.matchString(line 1872)
org.apache.xmlbeans.impl.regex.RegularExpression.matchString(line 1872)
...


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