Zach Brown wrote:
Again __set_bit()/__clear_bit() take unsigned long while chunk->size is
unsigned short. Can it cause problem if I cast this chunk->size to
unsigned long and pass to them?
_Yes_. That's what I said in the first mail and why I brought it up to
begin with! Maybe architectures (like i386!) implement it with assembly
that will write to the entire long when setting a given bit.
- z
Ok, then I will do with this (as posted earlier):
#define ChunkFree(chunk) \
(!!(chunk->size & (1 << CHUNK_FREE)))
#define SetChunkFree(chunk) \
(chunk->size |= (1 << CHUNK_FREE))
#define ClearChunkFree(chunk) \
(chunk->size &= ~(1 << CHUNK_FREE))
-- Nitin
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