static void Job6(Args _args)
{
str s;
try
{
s=runbuf("int myfunc(int i, str s) { print s; return i; }", 5, 126);
print s;
pause;
}
catch
{
info ("never reach this spot");
}
}If I omit an argument, or add an extra argument, arg3, to the runbuf(strCodeBlock,arg1,arg2,arg3,...), I get a compile error, and further progress in runtime stops. The exception cannot be caught by the exception handler, since the compilation stopped.
You must be sure, the codeblock has the arguments; which corresponds to the arguments given.
:-)
From: "agus.riyadi" <[EMAIL PROTECTED]>
Reply-To: [EMAIL PROTECTED]
To: "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
Subject: [development-axapta] try catch with runbuf
Date: Mon, 15 Dec 2003 10:49:30 GMT
Hi all,
Are there any way of catching error of runbuf method ?
I have a string containing code of a function that has two parameters.
I tried to call runbuf with those string as the first parameter and another parameter for the function. Of course it displayed error message since it needs two parameters.
But I wonder why can't I catch its error ? I have tried all possibilities of
the exception options, but none was able to catch the error.
Anybody have been dealt with this problem?
I will be glad for any clues, thanks :o)
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