you must set the caller to the form instead of the button by using :
args.caller(element);
instead of :
args.caller(this);
In your clicked()-method.
Regards
Palle
________________________________
From: Jesmond Giordimaina [mailto:[EMAIL PROTECTED]
Sent: 28. september 2004 13:32
To: [EMAIL PROTECTED]
Subject: Re: AW: [development-axapta] closing the caller form
Hi,
thanks for fast reply.
But it's still telling "FormButtoncontrol Object does
not have method close".
The code that opens the second form is this:
void clicked()
{
Args args = new Args();
//Passing args to form
Form frm = new Form('ShowCustTableData');
FormRun formRun;
;
args.object(frm);
args.caller(this);
formRun = classFactory.formRunClass(args);
formRun.init();
formRun.run();
formRun.wait();
}
The code that tries to close the form (from the second
form) is :
void clicked()
{
Args args = new args();
FormRun frm;
;
frm = element.args().caller();
frm.close();
}
reg
Jesmond
--- Matthias Schuster <[EMAIL PROTECTED]> wrote:
> Hi Jesmond,
>
> try this!
>
> FormRun frm;
> Frm = element.args().caller();
> Frm.close();
>
> Cu
> M
>
>
> _____
>
> Von: Jesmond Giordimaina
> [mailto:[EMAIL PROTECTED]
> Gesendet: Dienstag, 28. September 2004 11:05
> An: [EMAIL PROTECTED]
> Betreff: [development-axapta] closing the caller
> form
>
> Hi all,
>
> does anybody know how to close a form from another
> form? I am trying to use the following code from the
> active form.
>
>
> Args args = new args();
> Form frm;
> ;
>
> frm = args.caller();
> frm.finalize();
>
>
> Thanks in advance
> reg
> Jesmond
>
>
>
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