Hi,
you can extract it from properties as shown below. For convenience
write a method using DictEnum class to construct the path
(TreeNode::findNode(<PATH>)) by enum and value.
static void Job34(Args _args)
{
TreeNode TN;
str s;
;
TN = TreeNode::findNode("Data Dictionary\\Base
Enums\\AssetStatus\\Open");
if(TN)
{
s = strline(TN.AOTgetProperties(), 2);
s = substr(s, strscan(s, "@", 1, strlen(s)),strlen(s));
print s;
}
pause;
}
Regards,
Onno
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