Byteway,

I failed to mention that in the process of trying to make this work,
the DLL developers kindly created a test version that simply read
the values passed, wrote a log file of the values it saw, and exited
the DLL process.  Testing this proved out theory that the DLL was
getting good data from the call parameters.  Axapta received the
return value correctly and proceeded normally on down code.

You mention the "offset-count to the power of two", and how it
causes the DLL to write to something other than the expected memory
space.  Hmm.. since I'm fortunate enough to have the DLL modified to
meet our requirements by a group of math geniuses.
What's the possibility of compensating for the 2x factor within the
DLL to write to the location expected by Axapta?  This solution
could theoretically work, as long as Axapta allows dll right to
space it's reserved?

Thanks again,
Tim Peterson

--- In [email protected], Byteway <[EMAIL PROTECTED]>
wrote:
>
> Hi,
>
> Interresting topic, a couple of years ago I tried the same thing:
> accessing an array from a dll within Axapta. The result was that I
got
> the same behaviour as you describe - a hidden feature to close
Axapta
> even faster than my eyes can see ;-)
>
> Alternative:
> After some research I descovered that there is some kind of
standard to
> cope with these things. But it is only aplicable to com
interfaces.
> Google for ¨create COM next value methods".
> In pseudo code it goes like this:
> while (i get a next value from thirdpartydllmethod) { do something
with
> it }. Note that the method never passes an array, instead it
returns the
> next-value (until next value is null).
>
> Also what I discoverd in interfacing with third party dll's is
that the
> values given back in a fixed array, the offset to read the value
is the
> offset-count to the power of two. I don't know if I am clear
enough... I
> mean you can't just add the count of bytes to the previously read
value,
> to retrieve the next value. That way you would be reading
something
> which is not there, Axapta would go out of it's own boundries and
> windows will shut it down at ones.
>
> Can you give some more details on the peace of software you try to
> interface with? Perhaps there are better ways to this problem?
>
> Just some thoughts,
> /b
>
>
>
>
> tsk1958pete wrote:
>
> > Hi again All,
> > Using Tom's suggestions I was able to get the data passed with
> > apparent success to the DLL (see code below).  The problem is
that
> > as I step into the dll call line, the Axapta Application totally
> > crashes and it's icon disappears from the tool bar leaving me
looking
> > at the editor screen waiting for it to come out of the call!
> >
> > Axapta just disappears... poof gone.. no error warnings..
no "Send
> > Error to Microsoft... no nothin!!
> >
> > I suspect this is occurring at the point in the DLL logic where
it
> > attempts to write the solution to the binary space passed to it.
> > Anybody have any experience with this?
> >
> > Thanks to All
> > Tim Peterson
> >
> > CODE IS AS FOLLOWS:
> >
> > client static int runDLL()
> > {
> >     Dll           ringoDLL;
> >     DllFunction   LSsolveRingo2;
> >
> >     int     iRingoReturn;
> >     int     nIntParams,nDblParams;
> >
> >     Binary 
dParams,nParams,RMLength,RMCostCwt,RMAvail,FGCredit,Diam;
> >     Binary
> > EndDrop,Bundle,FGNeeded,FGMax,Iyldpt,Iyield,Indxrm,NumCopies;
> >     Binary  Infgup,Ifg,Ifup;
> >     Binary  Objval,Objbnd,numpats;
> >
> >
> >     // Declare Vars used to query output
> >     real oObjVal,oObjbnd;
> >     int  oNumPats;
> >
> >     ;
> >     // Binary array equivalents            CALC BASED ON TEST DAT
> >     nParams   = new Binary(20);   //   5 ints * 4 bytes =  20
> >     dParams   = new Binary(32);   //   4 dbl  * 8 bytes =  32
> >     RMLength  = new Binary(16);   //   2 dbl  * 8 bytes =  16
> >     RMCostCwt = new Binary(16);   //   2 dbl  * 8 bytes =  16
> >     RMAvail   = new Binary(16);   //   2 dbl  * 8 bytes =  16
> >     FGCredit  = new Binary(32);   //   4 dbl  * 8 bytes =  32
> >     Diam      = new Binary(32);   //   4 dbl  * 8 bytes =  32
> >     EndDrop   = new Binary(32);   //   4 dbl  * 8 bytes =  32
> >     Bundle    = new Binary(8);    //   2 ints * 4 bytes =   8
> >     FGNeeded  = new Binary(16);   //   4 ints * 4 bytes =  16
> >     FGMax     = new Binary(16);   //   4 ints * 4 bytes =  16
> >     Iyldpt    = new Binary(16);   //   4 ints * 4 bytes =  16
> >     Iyield    = new Binary(20);   //   5 ints * 4 bytes =  20
> >     Indxrm    = new Binary(400);  // 100 ints * 4 bytes = 400
> >     NumCopies = new Binary(400);  // 100 ints * 4 bytes = 400
> >     Infgup    = new Binary(400);  // 100 ints * 4 bytes = 400
> >     Ifg       = new Binary(400);  // 100 ints * 4 bytes = 400
> >     Ifup      = new Binary(400);  // 100 ints * 4 bytes = 400
> >
> >      // Binary objects for return solution
> >     Objval  = new Binary(8);
> >     Objbnd  = new Binary(8);
> >     numpats = new Binary(4);
> >
> >     // Define function parameters
> >     ringoDLL     = new DLL('c:\\RingoDLL\\ringo3');
> >     LSsolveRingo2 = new DLLFunction(ringoDLL,'LSsolveRingo2');
> >
> >     LSsolveRingo2.returns(ExtTypes::DWord);
> >     LSsolveRingo2.arg(ExtTypes::Pointer,    // nParams       int
> >                      ExtTypes::DWord,       // nIntParams    int
> >                      ExtTypes::Pointer,     // dParams       dbl
> >                      ExtTypes::DWord,       // nDblParams    int
> >                      ExtTypes::Pointer,     // RMLength      dbl
> >                      ExtTypes::Pointer,     // RMCostcwt     dbl
> >                      ExtTypes::Pointer,     // Bundle        int
> >                      ExtTypes::Pointer,     // RMAvail       dbl
> >                      ExtTypes::Pointer,     // FGNeeded      int
> >                      ExtTypes::Pointer,     // FGMax         int
> >                      ExtTypes::Pointer,     // FGCredit      dbl
> >                      ExtTypes::Pointer,     // Diam          dbl
> >                      ExtTypes::Pointer,     // EndDrop       dbl
> >                      ExtTypes::Pointer,     // Iyldpt        int
> >                      ExtTypes::Pointer,     // Iyield        int
> >                      ExtTypes::Pointer,     // Objval        Ptr
> >                      ExtTypes::Pointer,     // Objbnd        Ptr
> >                      ExtTypes::Pointer,     // Numpats       Ptr
> >                      ExtTypes::Pointer,     // Indxrm        int
> >                      ExtTypes::Pointer,     // Numcopies     int
> >                      ExtTypes::Pointer,     // Infgup        int
> >                      ExtTypes::Pointer,     // Ifg           int
> >                      ExtTypes::Pointer);    // Ifup          int
> >
> >
> >
> >     // Fill test data
> >     // The dWord(1,2) parameters ar 1 = Start byte offset  2 =
Value
> > placed in byte
> >     nintParams = 5;
> >     nParams.dWord( 0,  4);  // Numfps
> >     nParams.dWord( 4,  2);  // Numrm
> >     nParams.dWord( 8,100);  // Numpatsmx
> >     nParams.dWord(12,100);  // Numelsmx
> >     nParams.dWord(16, 60);  // Limsecs
> >
> >     nDblParams = 4;
> >     dParams.Double( 0,0.3400);  //  NeutralAxis
> >     dParams.Double(8,3.1900);  //  WtPerFt
> >     dParams.Double(16,0.0000);  //  Cpcut
> >     dParams.Double(24,3.14159); //  PI
> >
> >     RMLength.Double( 0,20.00);  //  Double
> >     RMLength.Double( 8,40.00);
> >
> >     RMCostcwt.Double( 0,30.43);  //  Double
> >     RMCostcwt.Double( 8,30.43);
> >
> >     Bundle.dWord( 0,1);  //  Integer
> >     Bundle.dWord( 4,1);
> >
> >     Rmavail.Double( 0,9999.99);  //  Double
> >     Rmavail.Double( 8,9999.99);
> >
> >     FGNeeded.dWord( 0,  4);  //  Integer
> >     FGNeeded.dWord( 4,  2);
> >     FGNeeded.dWord( 8,100);
> >     FGNeeded.dWord(12,100);
> >
> >     FGMax.dWord( 0, 20);  //  Integer
> >     FGMax.dWord( 4, 18);
> >     FGMax.dWord( 8,  6);
> >     FGMax.dWord(12,  3);
> >
> >     FGCredit.Double( 0,000.00);  //  Double
> >     FGCredit.Double( 8,000.00);
> >     FGCredit.Double(16,000.00);
> >     FGCredit.Double(24,000.00);
> >
> >     Diam.Double( 0, 12.7500);  //  Double
> >     Diam.Double( 8, 48.0000);
> >     Diam.Double(16, 61.0625);
> >     Diam.Double(24,132.0000);
> >
> >     EndDrop.Double( 0,14.000);  //  Double
> >     EndDrop.Double( 8,16.000);
> >     EndDrop.Double(16,16.000);
> >     EndDrop.Double(24,30.000);
> >
> >     Iyldpt.dWord( 0, 2);  //  Integer
> >     Iyldpt.dWord( 4, 3);
> >     Iyldpt.dWord( 8, 4);
> >     Iyldpt.dWord(12, 5);
> >
> >     Iyield.dWord( 0, 2);  //  Integer
> >     Iyield.dWord( 4, 1);
> >     Iyield.dWord( 8, 1);
> >     Iyield.dWord(12, 1);
> >     Iyield.dWord(16, 1);
> >
> >     // Initialize ObjVal, ObjBnd  and Numpats to 0
> >     Objval.Double(0,0.000);
> >     Objval.Double(0,0.000);
> >     Numpats.dWord( 0, 0);
> >
> >
> >     iRingoReturn = 9999;
> >     iRingoReturn = LSsolveRingo2.call
> > (nParams,nIntParams,dParams,nDblParams,RMLength,
> >                                     
> > RMCostCwt,Bundle,RMAvail,FGNeeded,FGMax,
> >                                     
> > FGCredit,Diam,EndDrop,Iyldpt,Iyield,
> >                                     
> > Objval,Objbnd,numpats,Indxrm,NumCopies,Infgup,
> >                                       Ifg,Ifup);
> >
> >     return iRingoReturn;
> > }
> >
> >
> >
> > --- In [email protected], "Thomas Jensen"
> > <[EMAIL PROTECTED]> wrote:
> > >
> > > Hi Tim
> > >
> > > Try using the Binary object in stead of the Array class:
> > >
> > > Binary binary = new Binary(8);
> > > Binary binary_out = new Binary(8);
> > >
> > > binary.dword(0,10);
> > > binary.dword(4,20);
> > >
> > > iReturn = _myFunction.call(iParam1,binary,binary_out)
> > >
> > > Regards
> > > Thomas
> > >
> > >
> > > ________________________________
> > >
> > > Fra: [email protected] på vegne af tsk1958pete
> > > Sendt: on 02-11-2005 23:00
> > > Til: [email protected]
> > > Emne: [development-axapta] Passing Arrays to and from 3rd
Party DLL
> > >
> > >
> > >
> > > Hi All,
> > >
> > > Trying to call a standard DLL (not com standard).  The
parameters
> > > passed in are an integer var and an array (input data) lastly
an
> > > empty array of 100 elements is passed that will be filled with
> > > solution data by the DLL. My problem is that the DLL is
getting the
> > > int parameter 1 correctly, but not either of the arrays.  I
didn't
> > > think I needed to designate pass by reference.
> > >
> > > Anybody have a solution
> > >
> > > I'm calling it as follows:
> > >
> > > client static int runDLL()
> > > {
> > >     Dll           _myDLL;
> > >     DllFunction   _myFunction;
> > >     int           iParam1,iReturn;
> > >     Array         iInParams,iOutSolution;
> > >
> > >     iInParams    = new Array(Types::Integer);
> > >     iOutSolution = new Array(Types::Integer);
> > >
> > >     _myDLL      = new DLL('c:\\mydll');
> > >     _myFunction = new DLLFunction(_myDLL,'myFunction ');
> > >
> > >     _myFunction.arg(ExtTypes::DWord,   // iParam1      int
> > >                     ExtTypes::Pointer, // nInParams    int
> > >                     ExtTypes::Pointer) // iOutSolution dbl
> > >  
> > >
> > >     iParam1 = 6
> > >     iInParams.value(1,10);
> > >     iInParams.value(2,20);
> > >
> > >     iOutSolution.value(1,0);
> > >     iOutSolution.value(2,0);
> > >
> > >     iReturn = 9999;
> > >     iReturn = _myFunction.call(iParam1,iInParams,iOutSolution)
> > > }
> > >
> > > Thanks for any help
> > > Tim Peterson
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > >
> > > [Non-text portions of this message have been removed]
> > >
> >
> >
> >
> >
> >
> >
> >
> >
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