On Wed, Feb 12, 2014 at 12:26:14PM +0100, Sebastian Hesselbarth wrote:
> You can cook it down to:
> 
>       m = matches;
>       /* Check against matches without compatible string */
>       while (m->name[0] || m->type[0] || m->compatible[0]) {
>               if (!m->compatible[0] && of_match_type_or_name(node, m)
>                       return m;
>               m++;
>       }

Will do.

Thanks,
Kevin

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