On Wednesday 05 November 2003 07:39 pm, Martin Stone Davis wrote:
> Tom Kaitchuck wrote:
> > Wait. Shouldn't that be
> > pSuccess*tSuccess +
> > pFailure*(tFailure+tGlobalSuccess+tTimeItTakesForTheOriginalNodeToFindOut
> >ItFailed). if it it's not, it should be. (note to self: need a better
> > varable name)
>
> Since it's the original node (our node) that is measuring all of this,
> tFailure includes tTimeItTakesForTheOriginalNodeToFindOutItFailed.

How do the intermediate nodes route then?

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