Summary: iota should work with floats
           Product: D
           Version: 2.030
          Platform: PC
        OS/Version: Windows
            Status: NEW
          Severity: normal
          Priority: P2
         Component: Phobos

import std.range;

void main() {
    auto foo = iota(0.0L, 10.0L, 1.0L);

The above doesn't compile and results in a bunch of long errors that aren't
particularly useful for diagnosing the cause of the problem.  The real problem
line 2089, range.d:

return take((end - begin + step - 1) / step, Seq(tuple(begin, step), 0u));

The problem is that, if the arguments to iota are floats, not ints, the number
of elements take() is told to take is a float, not an int.  This can be fixed
trivially by changing that line to:

return take(cast(size_t) ((end - begin + step - 1) / step), Seq(tuple(begin,
step), 0u));

Also, take() should probably use a ulong, not a size_t.  I could picture
someone wanting to run a long monte carlo simulation, for example, by taking
more than 4 billion elements from an infinite range of random numbers.

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