Summary: anonymous delegate with default parameters cross-talks
                    to another anonymous  delegate
           Product: D
           Version: 2.040
          Platform: Other
        OS/Version: Windows
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD

--- Comment #0 from Philippe Sigaud <> 2010-03-01 
18:36:25 CET ---
If you declare an anonymous delegate with default parameter, it affects another
anonymous delegate with the same type:

import std.stdio;
void main() {

    auto foo = (int a = 1) { return a;};
    auto bar = (int a) { return a;};

    writeln(foo()); // writes '1'
    writeln(bar()); // writes '1' also!

It provokes (correctly) an error if bar is defined before foo: bar() called
with 0 argument instead of 1.

It does not affect delegate with another type

    auto baz = (double a) { return a;}; 
    writeln(baz()); // Error, correct behaviour

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