--- Comment #7 from Lars T. Kyllingstad <> 2010-12-21 
00:56:37 PST ---
(In reply to comment #6)
> You are probably right. Then why isn't this a compile error?
> Foo f1 = scoped!Foo();

Because Scoped!Foo has an 'alias this' to the underlying Foo, which is
necessary for it to behave like a Foo.

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