--- Comment #9 from Andrei Alexandrescu <> 2011-04-06 
12:44:13 PDT ---
One can always connect an imaginary root to all rootless interfaces and apply
the rule I mentioned. Let me add that "?:" is a cornerstone operator for a lot
of traits and type deduction paraphernalia (e.g. std.traits.CommonType). I
wouldn't insist in the matter if it weren't important beyond the convenience of
"?:" itself.

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