yebblies <> changed:

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--- Comment #1 from yebblies <> 2011-07-03 14:28:33 EST ---
The issue here is in:

template func(T)
    static if (cond)
        void func(T x) {}

func is only a function template (onemember) when cond is true, and in the
general case cond may rely on T, which relies on ifti.

The following might illustrate it better:

template func(T)
    static if (is(T == int)) // how could we know this before performing ifti?
        void func(T* x) {}

The compiler cannot generally evaluate static if conditions without the
template args being known.  Although it could in very simple cases, I'm not
sure it's worth the effort.

One place I think this could be done is inside VersionConditions.

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