http://d.puremagic.com/issues/show_bug.cgi?id=6912
Steven Schveighoffer <schvei...@yahoo.com> changed:
What |Removed |Added
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CC| |schvei...@yahoo.com
--- Comment #1 from Steven Schveighoffer <schvei...@yahoo.com> 2011-11-09
06:35:05 PST ---
inout a = q;
This line should fail to compile. const does not implicitly cast to inout.
Note that:
immutable a = q;
doesn't work. inout should follow the same restrictions.
I don't think this has to do with transitivity (and indeed, inout cannot
override const or immutable). It's just a simple case of inout cannot be
implicitly cast from something else.
Remember, inout can get implicitly cast back to immutable or mutable upon
function return. I don't think inout should override *any* qualifiers without
casts.
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