http://d.puremagic.com/issues/show_bug.cgi?id=7131



--- Comment #3 from d...@dawgfoto.de 2012-01-18 11:27:48 PST ---
OK, std.string and std.regex should implicitly form
two overload sets. As the resolved set in std.string
is empty std.regex.split should be called.

http://www.d-programming-language.org/hijack.html

I will take a look at this when I find some time.

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