--- Comment #6 from 2012-04-04 11:11:46 PDT ---
>look it up from two scopes -- the template definition scope (i.e. bar.d) and 
>the scope where S is defined (i.e. foo.d).

I thought this too, although the need to extend unknown types
at the template scope will be limited.

There is one important use-case where this fails though.
Extending library types so that they fit a library template, e.g.
to use with std.algorithm.find I need to modify

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