http://d.puremagic.com/issues/show_bug.cgi?id=8508
Summary: std.traits.isSomeString no longer works with enums Product: D Version: unspecified Platform: All OS/Version: All Status: NEW Severity: regression Priority: P2 Component: Phobos AssignedTo: nob...@puremagic.com ReportedBy: jmdavisp...@gmx.com --- Comment #0 from Jonathan M Davis <jmdavisp...@gmx.com> 2012-08-04 14:20:31 PDT --- This code passes with 2.059 but fails with 2.060: import std.traits; enum E : string { a = "hello" } static assert(isSomeString!(typeof(E.a))); void main() { } It's commit https://github.com/D-Programming-Language/phobos/commit/52462bec6ea846f30e8dac309d63ccb4101e8f0c which broke this. Kenji Hara argues that enums should be treated as strongly typed by std.traits, but the language itself doesn't do this. auto func(string s) {...} will accept E.a just fine, but no auto func(S)(S s) if(isSomeString!S) {...} will not. Kenji also points out that std.traits has not been consistent with regards to how it treats enums, and enum U : uint { a = 0 } static assert(isUnsigned!(typeof(U.a))); fails with both 2.059 and 2.060. I'd argue that it should pass as well. Needing to distinguish between an enum of a particular base type and that exact type is quite rare AFAIK (std.conv.to and std.format care but not a lot else). As such, I really think that we'd be better off if std.traits treats enums as their base types and let code which cares about whether a particular template argument is an enum or not check whether it's an enum - that's what is(T == enum) is for. As it stands, it's _very_ easy to break code which uses enums when templatizing a function which wasn't previously templatized, and std.traits is completely inconsistent with the language with regards to enums. This needs to be fixed. -- Configure issuemail: http://d.puremagic.com/issues/userprefs.cgi?tab=email ------- You are receiving this mail because: -------